x^2+(25x)/2+36=0

Solution for x^2+(25x)/2+36=0 equation:

x^2+(25x)/2+36=0

We multiply all the terms by the denominator


x^2*2+25x+36*2=0

We add all the numbers together, and all the variables

x^2*2+25x+72=0

Wy multiply elements

2x^2+25x+72=0

a = 2; b = 25; c = +72;
Δ = b2-4ac
Δ = 252-4·2·72
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7}{2*2}=\frac{-18}{4}
=-4+1/2
$